Strings
Strings Practice & Revision
Master string pattern recognition with a decision tree framework, top 15 curated interview problems, and a revision cheat sheet.
Last Updated: August 2, 2026
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30 min read
1. Introduction
What is Strings Practice & Revision?
This lesson synthesizes all string representations, manipulations, and core algorithmic patterns into a unified String Pattern Recognition Framework.Why is it Important?
String questions are notoriously deceptive: brute force solutions involving string slicing or nested loops quickly time out (O(N²) / O(N³)). A structured decision tree lets you pick the optimal O(N) or O(N log N) algorithm within the first 3 minutes of an interview.
Where is it Used?
2. Mental Model
Think of string pattern recognition as a Diagnostic Decision Flowchart.
3. Concept: The String Pattern Decision Tree
Follow this exact decision workflow when presented with any string problem:
4. Visuals
Pattern Recognition Map
Note: Interactive Practice Table Available: Switch to the Practice Problems tab at the top of this lesson to interactively solve, track completion, watch video solutions, and take notes on all 15 must-solve string interview problems!
5. Real-World Examples
6. Interview Perspective
5-Step String Strategy
1. Clarify Character Set (1 min): Ask: "Is the string ASCII only? Lowercase English ('a'-'z') or Unicode?" 2. Beware Immutability (2 min): In Java/Python, state that you will use aStringBuilder or list of characters to avoid O(N²) concatenation costs.
3. Select Optimal Pattern (3 min): State why Frequency Array / Two Pointers / Sliding Window / KMP / Trie eliminates unnecessary sub-string copy passes.
4. Code Cleanly (10 min): Write modular code with clear variable names (left, right, charCount, isEndOfWord).
5. Dry-Run Edge Cases (4 min): Test empty strings "", single-character strings "a", and strings with no matching pattern.
7. Summary & Revision Cheat Sheet
8. Quiz
Question 1: What is the optimal time and space complexity to group a list of N strings of length L into anagram buckets?
Answer:O(N × L) time and O(N × L) space using a size-26 frequency tuple as the HashMap key.
Question 2: Why is string concatenation using += inside a loop an antipattern in Java and Python?
Answer: Because strings are immutable. Each+= allocates a new string object and copies all previous characters, resulting in O(N²) overall runtime.
Question 3: When should you use a Trie over a HashSet for string lookups?
Answer: Use a Trie when you need prefix matching (startsWith()), autocomplete suggestions, or shared prefix memory savings across millions of words.
Question 4: How does KMP achieve O(N + M) time complexity for substring matching?
Answer: By precomputing anO(M) LPS (Longest Prefix Suffix) table that lets the pattern pointer skip redundant comparisons without ever moving the text pointer backward.
Question 5: How do you handle even-length vs odd-length palindromes when expanding around a center?
Answer: For odd-length palindromes, expand around single character centers(i, i). For even-length palindromes, expand around adjacent character centers (i, i+1).